PHP use function return value as array -

Why is it that works:

  $ cacheMatchesNotPlayed = $ cache- & Gt; Load ('external data'); $ Cache matches notepadled = $ cash mats not played ['matches not played'];  

But it does not work:

  $ cacheMatchesNotPlayed = $ cache-> Load ('external data') ['machot plated'];  

Is there any reason for this? The second is easy to write.

The PHP function does not support array dereference, which you want to do.

See an RFC on the topic, and the affiliate mailing list conversation, which was rejected almost this year last year. Although there was support for this, and it is still a common request (usually "why do not it work? "), there is no plan in the proposal to implement this syntax.

Why , the code implementing it has not been submitted for approval (if it is written exactly).

Update

This feature has been implemented in PHP's Trunk (main development) branch and will be in the next non-bugfix version (5.4.0) Will be included. For anyone wishing to play with FAAD, A. Do not hesitate to download A / A.