Provides Flex 4 as descendant CSS selectors and pseudor selectors:
s | DropDownList: Open (font-size: 11;} S | DropDownList #labelDisplay {font-size: 12;}
However, if I want to do the same thing, then Do not think:
s | DropDownList: open #labelDisplay {font-size: 13;}
Is it possible with the pseudo-selectors of the lineage ?
(I see it looks like As such it may be a flex bug. When But, if you use the pseudor selector; Even empty, no style information; it seems to fix: I can see the same behavior in SDK 4.0, 4.1 and 4.5. Not so, but at least one is a workaround. styleName.open
at
: open
is not used in the pseudo-selector, then the lineage style Is not implemented, as you found:
s | dropdown list #label display (font-size: 12;) S | DropDownList: open #labelDisplay {font-size: 14; }
s | dropdown list #labelDisplay {font-size: 12;} / * fixes this line * / s | DropDownList: Open {} s | DropDownList: Open #labelDisplay {font-size: 14; }
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