I call this function on-the-homeover and for multiple devices on-house ID, 62, 63, 64,65 ... The function takes effect on slide with slide_it {$ ('# option_' + id). Sleelectogulle ('slow'); }
The problem is that if I move my mouse again and again the mouse has to be mouse-mouse again. If I do this several times, then the slide effect happens at the same time when I pulled my mouse out of the div and, as expected.
But I can not understand how I can do this once ? I can set a variable, but I have several divs used by this function and I can not think of a simple way of doing this instead of storing things in an array, but it is messy!
$ ('# options_' + id) .stop (True) .slideToggle ('slow');
:
When
.stop ()
is said on an element, currently running animation (if any If it is hidden, for example, if an element is being hidden with.slideUp ()
, then called.stop ()
, the element is now Will also be displayed, but one part is not called its previous height callback functions. Example: If you move fast and out, I do not wait to finish sliding it, it stops it and as soon as you release the mouse.
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